**56.** Match **List-I** with **List-II**: **List-I:** - (A) \( \text{Al}^{3+} < \text{Mg}^{2+} < \text{Na}^+ < \text{F}^- \) - (B) \( \text{B} < \text{C} < \text{O} < \text{N} \) - (C) \( \text{B} < \text{Al} < \text{Mg} < \text{K} \) - (D) \( \text{Si} < \text{P} < \text{S} < \text{Cl} \) **List-II:** - (I) Ionisation Enthalpy - (II) Metallic Character - (III) Electronegativity - (IV) Ionic Radii Choose the **correct answer** from the options given below: - (1) A-IV, B-I, C-III, D-II - (2) A-II, B-III, C-IV, D-I - (3) A-IV, B-I, C-II, D-III - (4) A-III, B-IV, C-II, D-I

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Published July 8, 2025
Chemistry
Periodic Table
Periodic Trends
Ionisation Enthalpy
Electronegativity
Metallic Character
Ionic Radii

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Detailed Explanation

Key Periodic Trends You Need

  1. Ionic Radii in Isoelectronic Series
    For ions with the same number of electrons, radius mainly depends on nuclear charge ZZ. More ZZ \Rightarrow stronger pull \Rightarrow smaller ion.

  2. Ionisation Enthalpy (IE)
    In one period IE usually rises left→right because electrons are pulled more tightly. There are small dips (e.g. B<Be\text{B} < \text{Be}, O<N\text{O} < \text{N}) due to subshell arrangements.

  3. Metallic Character
    • Increases down a group (outer electron farther away, easier to lose).
    • Decreases across a period (nuclear pull increases, electrons harder to lose).

  4. Electronegativity (EN)
    Generally climbs left→right in a period and falls top→bottom in a group.

How a student should think step-by-step

  1. Look for an isoelectronic sequence: (A) has Al3+,Mg2+,Na+,F\text{Al}^{3+}, \text{Mg}^{2+}, \text{Na}^+, \text{F}^-. All have 10 electrons → property must be ionic radius.
  2. Find a list with the special B, C, O, N irregularity: (B) mimics the well-known IE pattern with two dips, signalling ionisation enthalpy.
  3. Search for a trend that grows down & left: (C) B<Al<Mg<K\text{B} < \text{Al} < \text{Mg} < \text{K} clearly shows increasing metallic character.
  4. Anything left is likely EN: (D) climbs neatly across the period (Si → Cl), matching electronegativity.

Thus we connect:

  • A → Ionic Radii (IV)
  • B → Ionisation Enthalpy (I)
  • C → Metallic Character (II)
  • D → Electronegativity (III)

Simple Explanation (ELI5)

What is the question like?

We have four different orders of elements/ions. We must decide which property each order is describing:

  1. Sizes of ions
  2. How much energy it takes to pull off an electron (ionisation enthalpy)
  3. How easily an atom grabs electrons (electronegativity)
  4. How “metal-like” the element behaves (metallic character).

How do we decide?

Imagine lining up kids from shortest to tallest, or from calm to hyper. Each property is a kind of "line-up":

  • Ionic size – Think of the same number of marbles (electrons) squeezed by magnets (nuclear charge). More magnets (protons) pull marbles tighter → smaller ion.
  • Ionisation enthalpy – Pulling a lollipop (electron) from a kid. The stronger the kid holds it, the more energy you need.
  • Electronegativity – How greedy a kid is for other kids’ lollipops.
  • Metallic character – How likely the kid is to share electrons (metals love to share). It grows as you move down a group and falls as you move left → right in a period.

By matching each list to the correct "line-up", we find the answer.

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Step-by-Step Solution

Step-by-Step Matching

  1. Sequence (A): Al3+<Mg2+<Na+<F\text{Al}^{3+} < \text{Mg}^{2+} < \text{Na}^+ < \text{F}^- All ions are isoelectronic (10 e⁻). In such a series, larger Z    smaller radius\text{larger } Z \;\Rightarrow\; \text{smaller radius} The given order is smallest → largest radius, hence Ionic Radii (IV).

  2. Sequence (B): B<C<O<N\text{B} < \text{C} < \text{O} < \text{N} Experimental first-IE values (kJ mol⁻¹) roughly: 801 < 1086 < 1314 < 1402. This ascending order (with O lower than the general trend) matches Ionisation Enthalpy (I).

  3. Sequence (C): B<Al<Mg<K\text{B} < \text{Al} < \text{Mg} < \text{K} Moving down & left, metallic nature strengthens. Order fits Metallic Character (II).

  4. Sequence (D): Si<P<S<Cl\text{Si} < \text{P} < \text{S} < \text{Cl} Electronegativity (Pauling): 1.8 < 2.1 < 2.5 < 3.0. Therefore Electronegativity (III).

Final Matching

A-IV, B-I, C-II, D-III\boxed{\text{A-IV, B-I, C-II, D-III}}

Comparing with the options ⇒ Option (3) is correct.

Examples

Example 1

Radiation shielding materials rely on high ionic radii lead ions to pack atoms closely and block gamma rays.

Example 2

Aluminium’s moderate metallic character makes it ideal for lightweight structural alloys.

Example 3

The high electronegativity of chlorine makes it an effective disinfectant, pulling electrons from microbial membranes.

Example 4

Trends in ionisation enthalpy explain why nitrogen gas is inert: high IE discourages electron removal and reaction.

Visual Representation

References

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