The number of real solutions of x^7+5x³ +3x+1=0 is

3 min read
41 views
Published July 21, 2025
Mathematics
Algebra
Polynomials
Calculus
Monotonicity

💡 Want to ask your own questions?

Get instant explanations with AI • Free trial

Detailed Explanation

Key Ideas to Crack the Problem

  1. Odd-degree Polynomial: A polynomial of odd degree (here degree 77) must go to -\infty on one side and ++\infty on the other. Hence it must cross the xx-axis at least once.

  2. Monotonic Behaviour via Derivative:

f(x)=x7+5x3+3x+1,f(x)=7x6+15x2+3.\begin{aligned} f(x) &= x^7 + 5x^3 + 3x + 1, \\ f'(x) &= 7x^6 + 15x^2 + 3. \end{aligned}

• Every term in f(x)f'(x) is non-negative for all real xx.
• In fact, the constant 33 makes f(x)f'(x) strictly positive (>0>0) everywhere.
• Therefore f(x)f(x) is strictly increasing. A strictly increasing function cannot turn back – it hits any yy-value at most once.

  1. Combining 1 & 2:
    • Because f(x)f(x) starts from -\infty (as xx \to -\infty) and rises to ++\infty (as x+x \to +\infty) without ever slipping down, it must cross 00 exactly once.

Hence, number of real roots = 1.

Simple Explanation (ELI5)

🚂 Imagine a Train Track!

  1. Think of our equation x7+5x3+3x+1=0x^7 + 5x^3 + 3x + 1 = 0 as a long train track.
  2. The train (the graph) starts way down in the valley on the left (because x7x^7 is negative when xx is a big negative number).
  3. It keeps climbing up and up with no dips at all because the slope (speed) is always positive.
  4. Finally, when the train goes far to the right, it is very high in the sky (because x7x^7 is very positive).
  5. A track that only climbs and never comes down can cross the ground level (the xx-axis) exactly once.

So, there is only one place where the train touches the ground: one real solution.

👆 Found this helpful? Get personalized explanations for YOUR questions!

Step-by-Step Solution

Step-by-Step Solution

  1. Write the function:
    f(x)=x7+5x3+3x+1.f(x) = x^7 + 5x^3 + 3x + 1.

  2. Compute its derivative:
    f(x)=7x6+15x2+3.f'(x) = 7x^6 + 15x^2 + 3.

  3. Analyse the derivative:
    • For any real xx, 7x607x^6 \ge 0, 15x2015x^2 \ge 0, and the constant 3>03 > 0.
    • Therefore f(x)>0f'(x) > 0 for all xRx \in \mathbb{R}.
    • Hence f(x)f(x) is strictly increasing everywhere.

  4. Endpoint behaviour (degree consideration):
    • As xx \to -\infty, the leading term x7x^7 \to -\infty so f(x)f(x) \to -\infty.
    • As x+x \to +\infty, x7+x^7 \to +\infty so f(x)+f(x) \to +\infty.

  5. Conclusion:
    • A strictly increasing function that goes from -\infty to ++\infty must cut the xx-axis exactly once.

  6. Final Answer:
    1\boxed{1}

Examples

Example 1

Designing a ramp where the slope always increases ensures no flat spots, similar to how the derivative being always positive means one crossing.

Example 2

Economics: A steadily increasing demand curve (always upward-sloping) will intersect a fixed supply line at exactly one price.

Example 3

Physics: A monotonic potential energy function ensures only one equilibrium point where energy equals a chosen reference level.

Visual Representation

References

🤔 Have Your Own Question?

Get instant AI explanations in multiple languages with diagrams, examples, and step-by-step solutions!

AI-Powered Explanations
🎯Multiple Languages
📊Interactive Diagrams

No signup required • Try 3 questions free